let a{x:x belongs to r ,x^2 -6x +8 =0} and b= {x:x belongs to n ,x^2 =16} find b-a
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R={(x,y):x,y∈z,x−yisdivisiblebyn}ForReflexive,x∈zSo⇒(x−x)isdivisiblebyn⇒(x,x)∈z
So, Relation is Reflexive
ForSymmetric⇒Let(x,y)∈R⇒(x−y)isdivisiblebyn.⇒nx−y=c,Remainderis0.⇒ny−x=−c,Remainderisalso0.⇒(y−x)isdivisiblebyn(y,x)∈RSo,RisSymmetric.ForTransitive⇒Let(x,y)∈R&(y,z)∈R⇒(x−y)isdivisiblebyn⇒(y−q)isdivisiblebyn
add both these equation (i) & (ii)
(x−y)=xc,c∈z−v,(y−q)=na,(a∈z)⇒(x−y+y−q)=nc+na,c,
So, R is Transitive
So, the R is Reflexive, Symmetric and Transitive
Then it is Equivalence Relation.
Step-by-step explanation:
i hope this answer is helpful
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