Let A= {x : x is a natural number and a factor of 18}
B= {x : x is a natural number less than 6}
Find: A ∪ B and A ∩ B
Answers
Answer:
{1,2,3}
A={1,2,3,6,9,18}
B={1,2,3,4,5}
therefore,A∩B {1,2,3}
Answer:
A ∪ B = {1, 2, 3} and A ∩ B = {1, 2, 3, 4, 5, 6, 9, 18}
Step-by-step explanation:
Given :- A= {x : x is a natural number and a factor of 18}
B= {x : x is a natural number less than 6}
To Find :- A ∩ B and A ∪ B
Solution :-
Natural number is a number that includes all the whole numbers except 0.
Prime Factorization of 18
= 2 × 3 × 3
∴ The factors of 18 are 1, 2, 3, 6, 9, 18.
∴ A = {1, 2, 3, 6, 9, 18}
Natural numbers less than 6 are:
1, 2, 3, 4, 5
∴ B = {1, 2, 4, 3, 5}
Now, A ∪ B = {1, 2, 3, 6, 9, 18} ∪ {1, 2, 3, 4, 5}
= {1, 2, 3}
A ∩ B = {1, 2, 3, 6, 9, 18} ∩ {1, 2, 3, 4, 5}
= {1, 2, 3, 5, 4, 6, 9, 18}
Therefore, A ∪ B = {1, 2, 3} and A ∩ B = {1, 2, 3, 4, 5, 6, 9, 18}
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