let a = {x:x is positive integral multiple of 3 less than 31}and b = {x:x is prime number less than 30} ,then n ( aub) +n(aub) is equal to :
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integral multiples of three less than 31 are 3,6,9,12,....30
prime no less than 30:2,3,5,7,11,13,17,23,29
N(aUB)=10+9=19 since bo of elements in a are 10 and in b are 9
so now n (a intersection b)= all common elements in a and b i.e. 3 (1 element)
so an (aUB) +n(anb)=19+1=20
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