Physics, asked by PhysicsHelper, 1 year ago

Let A1 A2 A3 A4 A5 A6 A1 be a regular hexagon. Write the x- components of the vectors represented by the six sides taken in order. Use the fact that the resultant of these six vectors is zero, to prove that

cos0+cosπ/3+cos2π/3+cos3π/3+cos4π/3+cos5π/3=0

Use the known cosine values to verify the result.


BrainlyYoda: Concept of Physics - 1 , HC VERMA , Chapter - "Physics and Mathematics"

Answers

Answered by BrainlyYoda
76
Thanks for asking the question!

ANSWER::

The thing which we knows is that according to polygon vector addition , the resultant of these vectors is 0.

In magnitude terms , A=B=C=D=E=F

So, resultant of x component=Acos0+Acosπ/3+Acos2π/3+Acos3π/3+Acos4π/3+Acos5π/3 = 0

As resultant is 0 , x component of resultant = 0

i.e. cos0+cosπ/3+cos2π/3+cos3π/3+cos4π/3+cos5π/3 = 0

And same as we proved above,

sin0+sinπ/3+sin2π/3+sin3π/3+sin4π/3+sin5π/3 = 0

Hope it helps you!


Attachments:
Answered by kolipallavi214
2

Explanation:

ANSWER

According to polygon vector addition, the resultant of given vectors is zero.

In the term of magnitude, A

1

=A

2

=A

3

=A

4

=A

5

=A

6

=A

So, resultant of X component=

=Acos0+Acos

3

Π

+Acos

3

+Acos

3

+Acos

3

+Acos

3

=0

As resultant zero, X component= 0 and same is proved in the given data

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