Let a1 a2 a3 a4 be real numbers such that a1+a2+a3+a4=0
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Since a1^2+a2^2+a3^2+a4^2=1
and the smallest possible value of expression (a1-a2)^2+(a2-a3)^2+(a3-a4)^2+(a4-a1)^2=0
If a1=a2=a3=a4=+/-1/2=
0.5 ans
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0,1.5 is the answer
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