Math, asked by Bittu7560, 1 year ago

Let a1 a2 a3 a4 be real numbers such that a1+a2+a3+a4=0

Answers

Answered by Anonymous
0

Answer:

Since a1^2+a2^2+a3^2+a4^2=1

and the smallest possible value of expression (a1-a2)^2+(a2-a3)^2+(a3-a4)^2+(a4-a1)^2=0

If a1=a2=a3=a4=+/-1/2=

0.5 ans

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Answered by theintelligent99
0

Answer:

0,1.5 is the answer

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