Let AB and CD be two line segments such that AD and BC intersect at O. Suppose AO = OC and BO = OD. Prove that AB = CD.
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Given : AB and CD two line segments
such that AD and BC intersect at O.
AO = OC
BO = OD
To prove : AB = CD
proof :
In ∆AOB and ∆COD
AO = OC ( Given )
<AOB = <COD ( vertically opposite angles )
BO = OD ( Given )
Therefore ,
∆AOB ≅ ∆COD
[ SAS congruence rule ]
AB = CD [ C.P.CT ]
••••
such that AD and BC intersect at O.
AO = OC
BO = OD
To prove : AB = CD
proof :
In ∆AOB and ∆COD
AO = OC ( Given )
<AOB = <COD ( vertically opposite angles )
BO = OD ( Given )
Therefore ,
∆AOB ≅ ∆COD
[ SAS congruence rule ]
AB = CD [ C.P.CT ]
••••
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Answered by
2
Hey there!
Step-by-step explanation:
Given,
AB and CD are line segments.
AO = OC
and BO = OD
To prove : AB = CD.
Proof:
Statement (Reason)
in ΔAOB and ΔCOD,
AO = OC (given)
BO = OD (given)
∠AOB = ∠COD (vertically opp. ∠s)
ΔAOB ≅ ΔCOD ( By SAS axiom)
AB = CD (cpctc)
Hope It Helps You!
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