Question

Let AB and CD be two parallel lines and line PQ be a transversal. Let PQ intersect AB in L . Suppose the bisector of angle ALP intersect CD in R and the bisector of angle PLB intersect CD in S . Prove that angle LRS + angle RSL =90DEGREE

Answer 1

Answer:

2 by 3 is equal to 4 by 5 is equal to 3