Question

Let AB be any chord of the circle x² + y² – 2x – 6y – 6 = 0 which subtends right angle at the point (2, 4), then the locus of the mid point of AB is_______ (A) x² + y² – 3x – 7y –16 = 0 (B) x² + y² – 3x – 7y + 7 = 0 (C) x² + y² + 3x + 7y – 16 = 0 (D) x² + y² + 3x + 7y – 7 = 0

Answer 1

Answer:

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