Question

Let AB be the diameter of the circle with centre O and C be any point on the circumference such that AC is 2.4 and BC is 3.2cm Find AB

Answer 1

Answer:

4 cms

Step-by-step explanation:

The angle formed will be a 90 at the point C

thus AB becomes the hypotnuse

By Pythagoras theorem

AB^2 = AC ^2 + BC^2

= 2.4^2 + 3.2^2

= 5.76 + 10.24 = Sqrt (16) = 4