Question

Let ABC and DEF are similar triangles and their areas be respectively 64 cm2 and 121 cm2. If EF = 15.4 cm, then BC is equal to

Answer 1

hey !!

refer the attachment for answer

hope it helps u :)).

( sorry if u don't understand my handwriting )


# Nikky

Answer 2

$\frak {\underline{\orange{Answer}}}$

Area of ∆ ABC = 64 cm²

Area of ∆ DEF = 121 cm²

We know that :-

∆ ABC $\sim$ ∆ DEF

We also know :-

$\sf \frac{ar(ABC)}{ar(DEF)} = {(\frac{AB}{DE} )}^{2}= {(\frac{BC}{EF} )}^{2}={(\frac{AC}{DF} )}^{2}$

$\sf \frac{64}{121} = { (\frac{(BC)}{(15.4)}) }^{2}$

$\sf \frac{BC}{15.4} = \sqrt{ \frac{64}{121} }$

$\sf \frac{BC}{15.4} = \frac{8}{11}$

$\sf BC = \frac{8}{11} \times 15.4$

$\boxed{\purple{\sf{ BC = 11.2}}}$

BC = 11.2 cm