Question

Let ABC be a right triangle in which AB=6cm,BC=8cm and B=90°.BD is the perpendicular from B on AC. The circle through B,C,D is drawn. Construct thetangent from A to this circle.

Answer 1

Hey user !!

your answer is attached above!!

Answer 2

Answer:

Step-by-step explanation:

Steps of construction:

1. Draw a line segment BC = 8 cm

. 2. Make a right angle at the point B i.e., ∠CBX = 90°

3. Draw a are of radius 6 cm as centre B which intersect BX at the point A. 4. Join AC  so, ABC is required right angle triangle.

5. Draw a arc taking centre B which intersect AC at the point K and L respectively taking K and L centre draw two arcs of same radius which intersect at the point M.

6. Join BM so, ∠BDC = 90°

7. Draw perpendicular bisector of BC.

8. Draw a circle taking radius equal to OB and centre O which passes through B, D and C.

9. Draw a arc taking centre A and radius equal to AB intersect the circle at point P so, AP is the tangents