Question

Let ABC be a right triangle in which AB =6cm ,BC=8cm and <B =90°•BD is the perpendicular from B on AC .the circle through B,C,D is drawn construct the tangent from A to the circle .

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Let ABC be a right triangle in which AB = 6 em. BC =

8 em and 4B = 90. BD is the perpendicular from B on

AC. The circle through B. C. D is drawn. Construct the

tangents from A to this circle.

Ans. To construct: A right triangle ABC with AB = 6 em.

BC = 8 cm and B 0. BD is the perpendicular from

B on AC and the tangents from A to this circle.

Steps of Construction:

(a) Draw a right triangle ABG with AB = 6 cm. BC = 8 cm

andB = 90. Also. draw perpendicular BD on AC.

(b) Join AO and bisect it at M (here O is the centre of

circle through B. G. D).

Step-by-step explanation:

(c) Taking M as centre and MA as radius. draw a circle.

Let it intersects the given circle at the points B and E.

(d) Join AB and AE.

Then AB and AE are the required two tangents.

Justification Join OE.

Then.

Z AEO is an angle in the semicircle.

AEO = 90

AE OE

Since OE isa radius of the given circle. AE has to be a

tangent to the circle. Similarly. AB is also a tangent to the

cirele.