Question

Let ABC be a traingle such that ∠B=70° and ∠C=40°. Suppose D is a point on BC such that AB=AD. Prove that AB>AC

Answer 1

In ∆DAB ,

AD = AB ---( 1 ) [ Given ]

<ADB = <ABD = 40° ---( 2 )

[ Angle opposite to equal sides

are equal ]

<ADB is exterior angle for ∆ACD

So, <ADB greater than <ACD

or <ABD greater than <ACD [ from (2)]

or <ABC greater than <ACB

AC > AB

[ Side opposite to larger angle is longer ]

AC > AD [ From ( 1 ) ]

••••

Answer 2

Step-by-step explanation:

Due to his nervousness, the narrator was unable to even write

his name on the blackboard. Even after the teacher tried to

help him, he still couldn’t manage this simple task. this made

the other students laugh.

3. Richard was very angry with himself. He could read better

than any of the students, write as well as them and fluent and

articulate when he was himself. Yet, he was furious with his

inability to simply write his name.

C. Think and Answer.

1. The other students could have been a little more thoughtful

towards Richard. They knew he was a new student and

therefore, should have tried to understand his nervousness.

Instead of laughing at him, some of them could have tried to

say encouraging words