Let ABC be a triangle and D and E be two points on side AB such that
AD=BE. IFDP || BC and EQ || AC, then prove that PQ || AB.
Can anyone tell the answer...........
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Answer:
Given= ABC is a triangle such that AD = BE also DP // BC and EQ // AC.
Prove that:- PQ//AB.
Proof:-
In the triangle ADP and EBQ;
=> AD= BE (given).
=> Angle (DAP) = Angle (BEQ).
[ corresponding interior angles]
=> Angle (ADP) = Angle (EBQ).
[ corresponding interior angles]
Therefore,
By, ASA congruency triangle (ADP) is congruent to triangle (EBQ).
Thus,
=> By CPCT:- PD=BQ ------(1).
=> And PD//BQ [given] ------(2).
Now,
since one pair of opposite side are equal and parallel.
Therefore, the quadrilateral DPQB is a parallelogram and PQ//DB. (hence proved ).
Hope it helps you,
Thank you.
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