Math, asked by sidsanu0, 9 months ago

let ABC be a triangle and M be a point on side AC closer to vertex C than A. let N be a point on side AB such that MN is parallel to BC and let P be a point on side BC such that MP is parallel to AB. if area of quadrilateral BNMP is equal to 5/18th area of triangle ABC, then ratio of AM/MC equals.
a)5 b)6 c)18/5 d)15/2

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Answered by mohdsohail81103
2

this is your answer.....................................

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