Question

Let ABC be a triangle and PQRS be a square with P on AB, Q on AC and R

and S on BC (possibly extended). Let H be on BC (possibly extended) such

that AH is the altitude of the triangle from A to the base BC.Then

(1) 1/AH + 1/PQ = 1/BC

(2) 1/PQ + 1/BC = 1/AH

(3) 1/AH +1/BC = 1/PQ

(4) 1/AH + 1/BC = 2/PQ

(5) NONE

Answer 1

Answer:

pls tell the figure

Step-by-step explanation:

it is really confusing