Question

Let ABC be a triangle and PQRS be a square with P on AB, Q on AC and R
and S on BC (possibly extended). Let H be on BC (possibly extended) such
that AH is the altitude of the triangle from A to the base BC.Then
(1) 1/AH + 1/PQ = 1/BC
(2) 1/PQ + 1/BC = 1/AH
(3) 1/AH +1/BC = 1/PQ
(4) 1/AH + 1/BC = 2/PQ

Answer 1

Answer:here's your answer

Step-by-step explanation:

its me Shashank, pranav bro I am also not able to solve this question so I left it

But still u r asking for answers ,unbelievable.no problem sometimes it happens.