Let ABC be a triangle. Draw a triangle BDC externally on BC such that AB = BD and AC = CD. Prove that ΔABC ≅ ΔDBC.
Answers
Answered by
2
Hope it helps!!!(and most probably it is write)
Attachments:
Answered by
1
Answer:
Δ ABC ≅ Δ DBC
Step-by-step explanation:
in Δ ABC & Δ DBC
BC = BC ( common)
AB = BD given
AC = CD given
as all corresponding sides are equal hence both the triangles are equilateral
=> Δ ABC ≅ Δ DBC
A
/ \
/ \
B /____\ C
\ /
\ /
\ /D
Similar questions