Let ABC be an equilateral triangle. If the co-
ordinates of A are (1,2) and co-ordinates of B
are (2, -1), then
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Let ABC be an equilateral triangle. If the co-
ordinates of A are (1,2) and co-ordinates of B
are (2, -1), thenIn △ABD and △CBD
AB = CB (Given)
AD = CD (Given)
BD = BD (Common)
By SSS test of congruency
△ABD ≅ △CBD(D) (1,-3)
Since, seg AB || Y-axis.
∴ x co-ordinate of all points on seg AB will be the same,
x co-ordinate of A (1, 3) = 1
x co-ordinate of B (1, – 3) = 1
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