let ∆ABC~∆DEF and their areas be respectively 64cm2 and 121cm2.if EF=15.4cm find BC
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here is your answer
we have studied theorm: area of similar triangles
The ratio of the areas of two similar triangles is equal to their square of the ratio of their corresponding sides.
Therefore.
Area of∆ABC/Area of ∆DEF=BC/EF
64/121=(BC/15.4)^2
64/121=BC/237.16
BC×121=15178.24
BC=15178.24/121
BC=125.44cm
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