Let ∆ABC ~ ∆DEF. If ar(∆ABC) = 225 cm2
, BC = 3 cm and EF = 7 cm, then find ar(∆DEF).
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△ABC∼△DEF
⟹Ar(ΔDEF)Ar(ΔABC)=(EFBC)212164=(15.4BC)2BC=12164×15.4BC=118×15.4=11.2cm
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