Let ABCD be a circumscribed quadrilateral to a given circle. Show that circles inscribed in the two triangles ABC and ADC touch each other.
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Given: ABCD be a circumscribed quadrilateral to a given circle.
To find: Show that circles inscribed in the two triangles ABC and ADC touch each other.
Solution:
- Now we have given that a quadrilateral ABCD is there, AC is joined.
- Let the circle inscribes in ABC be x1 and circle inscribes in ADC be x2.
- Let the point touching circle x1 and line AC be P and he point touching circle x2 and line AC be Q.
- Then:
PQ = AQ - AP
PQ = 1/2(AD+AC-DC) - 1/2(AB+AC-BC)
PQ = 1/2(AD-DC-AB+BC) = 0
Answer:
So the quadrilateral is circumscribed as PQ = 0.
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