Let ABCD be a trapezium in which AB is parallel to CD AB<11 cm ,BC=4 cm ,CD=6 cm and DA=3cm .The distance between AB and CD is a)2 b)2.4 c)2.8 d)Not determinable with the data
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1/2×3.5+5.5×3.5
=15.75
90/360×22/7×3.5×3.5
=1/4×22/73.5×3.5
=9.625
=15.75-9.625
=6.125cm^2
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