Question

let ABCD is a quadrilateral shaped field where AB= 5.5m, BC= 6.4m, CD= 4.5m, AD=4.8m and BD=7m. Find the area of the field

Answer 1

Step-by-step explanation:

in triangle ABD,

a=5.5m b=4.8m c=7m

S= a+b+c/2 = 5.5+4.8+7= 13.8

area of triangle ABD =

$\sqrt{s(s - a)(s - b)(s - c)}$

$\sqrt{13.8(13.8 - 5.5)(13.8 - 4.8)(13.8 - 7)}$

$\sqrt{13.8 \times 8.3 \times 9 \times 6.8}$

$3 \sqrt{13.8 \times 8.3 \times 6.8}$

=

$83.72$