Question

Let ABCDbe a parallelogram whose diagonals intersect at P and let O
be the origin, then OA + OB + OC + OD equal to

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

Answer:

Consider the problem

Since

P which is the intersection of diagonals of parallelogram its bisects the diagonal

Thus

OP=

2

(OA+OC)

i.e.

OA+OC=2OP ----- (i)

Similarly

OB+OD=OP ----- (ii)

Adding (i) and (ii)

we get

OA

+

OB

+

OC

+

OD

=4

OP

Step-by-step explanation:

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