Question

Let ABCDEF be a regular hexagon with
centre 'O' show that
AB+AC+ AD+AE+AF = 3AD=6AO​

Answer 1

Answer:

Sol: AB + AC + AD + AE + AF = AB + (AC +

AF) + AD + AE

= AB + (AC + CD) + AD + AE -

(Since AF = CD)

= 2AD + (AB+ AE)

= 2AD + ED + AE (Since AB = ED)

= 2AD + AD

= 3AD

3(2AO) = 6AO

(Since O is centerand AD = OD)

Thus

AB + AC + AD + AE + AF = 6AO