Let AD be an altitude in a right triangle ABC with
ZA= 90° and D on BC. Suppose that the radii of the
incircles of the triangles ABD and ACD are 33 and 56
respectively. Let r be the radius of the incircle of
triangle ABC. Find the value of 3(r +7).
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Answer:
The answer is pie = 22/7
Step-by-step explanation:
3(r+t)
r/d=22/7 = pie
Hope it helps
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