Question

let alpha
and ß
are
roots
x²
6x-2=0
with
a>ß , if
an=alphaň-betaň

for
n>_1
then the
value
of
a¹⁰-2a⁸÷2a⁹ is​

Answer 1

Answer:

the value is -35

Step-by-step explanation:

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