Math, asked by IronMan2624, 10 months ago

Let alpha and beta be roots of the quadratic equation (x-2)(x-3)+(x-3)(x+1)+(x+1)(x-2)=0 find the value of 1/(alpha+1)(beta+1) +(alpha-2)(beta-2)+1/(alpha-3)(beta-3)

Answers

Answered by sapnakasana723
1

Answer:

— 6 is the best answer to the fact

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