let alpha beta be the root of the equation x minus A into x minus b is equal to C C is not equal to zero then the root of the equation x minus 1 into x minus beta + C is equal to zero
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(x – \alpha)(x – \beta)=c
x2 – (\alpha + \beta)x +\alpha \beta = c (eqn 1 )
also
(x-a)(x-b) +c=0
x2 – (a+b)x +ab + c = 0
\alpha +\beta =a+b
\alpha\beta = ab + c
now eqn 1 becomes
x2 – (a+b)x + ab + c = c
x2 – (a+b)x + ab = 0
and roots of this equation are a and b
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