Let alpha beta gama be distinct real numbers the points with position vectros alpha i +beta j+ gama k, beta i+gama j+aplha k,gama i +aplha j +beta k are collinear, form equilateral trianlge, scalene triangle or a right angled triangle?
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HimanshiKankane:
U proved that the sides are equal so it's an equilateral triangle but how can we say that they are not collinear
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Let the points be denoted by A,B and C Then
|AB|=(β−α)2+(γ−β)2+(α−γ)2)−−−−−−−−−−−−−−−−−−−−−−−−−√
|BC|=(α−β)2+(α−γ)2+(α−β)2)−−−−−−−−−−−−−−−−−−−−−−−−−√
|CA|=(α−γ)2+(β−α)2+(γ−β)2)−−−−−−−−−−−−−−−−−−−−−−−−−√
Since AB=BC=CA
=> ABC is an equilateral triangle .
Answer : form an equilateral triangle
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