Let an=(0.1)^n for all n belongs to N and €=0.00002.find the N such that aN+1,aN+2,... belongs to (-€,€)
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Given : aₙ = (0.1)ⁿ for all n belongs to N and €=0.00002.
aN+1,aN+2,... belongs to (-€,€)
To Find : N
Solution:
€=0.00002
=> € = 2 x 10⁻⁵
- € = -2 x 10⁻⁵
€ = 2 x 10⁻⁵
-2 x 10⁻⁵ < (0.1)ⁿ < 2 x 10⁻⁵
(0.1)ⁿ > 0 hence only need to check
(0.1)ⁿ < 2 x 10⁻⁵
0.1³ = 1 x 10⁻⁴ > 2 x 10⁻⁵
0.1⁴ = 1 x 10⁻⁵ < 2 x 10⁻⁵
0.1⁵ = 1 x 10⁻⁶ < 2 x 10⁻⁵
0.1⁶ = 1 x 10⁻⁷ < 2 x 10⁻⁵
=> n ≥ 4
n = N+ 1, N + 2 ,....................
Hence N = 3
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