Math, asked by quadraj172, 8 months ago

Let Δ be the area of a triangle. Find the area of a triangle whose each side is twice the side of the given triangle.

Answers

Answered by RJ1729
0

Step-by-step explanation:

Attachments:
Answered by mad210206
0

Answer:

The area of the new triangle is 4 times of the area of the given triangle.

Step-by-step explanation:

  • Let, b is the base and h is the height (altitude) of the given triangle.
  • So, area of the triangle Δ =  \dfrac{1}{2} × b × h
  • ∵ the each side of the new triangle is twice the each side of the given triangle.
  • ∴ the base and the altitude of the new triangle will be 2b and 2h.
  • ∴ the area of the new triangle = \dfrac{1}{2} \\ × 2b × 2h

                                                   = \dfrac{1}{2}\\ × b × h × 4

                                                   = 4 Δ

so,the area of the new triangle is 4 times of the area of the given triangle.

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