Question

Let Δ be the area of the triangle with vertices (-2,-3), (3,2) and (-1,-8), then Δ is

Give me correct answer ✌​

Answer 1

Answer:

Step-by-step explanation:

Given,

A = (-2 , -3)

B = (3 , 2)

C = (-1 , -8)

To Find :-

Area of the triangle(Δ).

Formula Required :-

$Area\:of\:the\:triangle=\dfrac{1}{2}|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|$

Solution :-

$x_1,y_1=-2 , -3$

$x_2 , y_2 = 3 , 2$

$x_3 , y_3 = -1 , -8$

Area of the triangle :-

$=\dfrac{1}{2}|-2(2-(-8))+3(-8-(-3))+-1(-3-2)|$

$=\dfrac{1}{2}|-2(10)+3(-5)+-1(-5)|$

$=\dfrac{1}{2}|-20-15+5|$

$=\dfrac{1}{2}|-35+5|$

$=\dfrac{1}{2}|-30|$

$=\dfrac{30}{2}$

= 15 sq.units