Let ω be the complex cube root of unity. Consider the set
E={(a,b,c) ∈ R³ : ![\left[\begin{array}{ccc}ω&a&1\\0&c&1\\1&-b&ω\end{array}\right]](https://tex.z-dn.net/?f=+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%CF%89%26amp%3Ba%26amp%3B1%5C%5C0%26amp%3Bc%26amp%3B1%5C%5C1%26amp%3B-b%26amp%3B%CF%89%5Cend%7Barray%7D%5Cright%5D+ "\left[\begin{array}{ccc}ω&a&1\\0&c&1\\1&-b&ω\end{array}\right]")
DET =0 then E=
manitkapoor2:
R^3?
yes its R^3
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the answer is R^3.
hope this helps u !!!
hope this helps u !!!
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