Question

Let  be the vertices of triangle OPQ .The point R inside the triangle OPQ is such that the triangles OPR, PQR, OQR are of equal area. The point S is such that OS = PS = QS. Then   48 RS​

Answer 1

Answer:

Area of ∠ORQ=13∠ORQ=13Area of ∠OPQ∠OPQ

=13⋅12⋅4⋅6=13⋅12⋅4⋅6

=4unit2=4unit2

Areaof ∠ORQ=12⋅h⋅6∠ORQ=12⋅h⋅6

4=3h4=3h

h=43h=43

Co-ordinates of R(3,43)R(3,43).

Step-by-step explanation:

Let O(0, 0), P(3,4), Q(6, 0) be the vertices of the triangle OPQ. The point R inside the triangle OPQ is such that the triangles OPR,PQR, OQR are of equal area. The coordinates of R are

A

(

3

4

,3)

B

(3,

3

2

)

C

(3,

3

4

)

D

(

3

4

,

3

2

)

Answer 2

Answer:

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Step-by-step explanation:

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