Physics, asked by holani, 1 year ago

Let C = A + B then
(a) 1C is always greater then | A|
(b) It is possible to have IČKI Ā| and ICIIBU
(c) C is always equal to A + B
(d) C is never equal to A + B​

Answers

Answered by shlokpanditfbd
16

Answer:B

Explanation:

Answered by talasilavijaya
0

Answer:

Possible to have |C| < |A| and |C| < |B|

Explanation:

Given the magnitude of a vector that is equal to the sum of magnitudes of two vectors, i.e., C = A + B

Let us draw two vectors A and B using head-to-tail method. Taking vector B from the head of the vector A. Taking them as two adjacent sides of a triangle, join the tail of vector A with the head of the vector B. This gives the sum of the two vectors, a vector C.

Depending on the directions and magnitudes of two vectors A and B, the magnitude of vector C can be analyzed.  

  1. Vector C can be greater or less than the magnitude of vector A, so option (a) is wrong.
  2. Possible to have ||\vec C| &lt; |\vec A| and |\vec C| &lt; |\vec B| as shown in the figure. So, option (b) is correct.
  3. Equal to the sum of magnitudes of A and B; |\vec C|=|\vec A|+|\vec B| when they are in the same direction, so option (c) is wrong.
  4. Possible to have equal to, less or more than the sum of magnitudes of A and B,  so option (d) is wrong.

So, option b is the correct answer.

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