Let capacitance of three identical capacitors in series is 1
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Equivalent Capacitance = C = 1
By formula,
1/C = 1/C1 + 1/C2 + 1/C3
But all three capacitors have same capacitance
C1 = C2 = C3
Therefore,
1/1 = 3/C1
C1 = 3
Thus all three capacitors have 3 capacitance.
"Thanks"
By formula,
1/C = 1/C1 + 1/C2 + 1/C3
But all three capacitors have same capacitance
C1 = C2 = C3
Therefore,
1/1 = 3/C1
C1 = 3
Thus all three capacitors have 3 capacitance.
"Thanks"
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