Question

Let chairs be = x
let tables be = y
2x + 3y = 460 ------(1)
5x + 4y = 800 ------(2)
x = 460 - 3y / 2 ----(3)
Substitute eqn (3) in (2)
5 × (460 - 3y / 2) + 4y = 800
= 5 × (460 - 3y) + 4y = 1600
= 2300 - 15y + 4y = 1600
= 2300 - 1600 = 15y - 4y
700 = 11y
y = 700/11
Substitute y in eqn (3)
x = 460 - 3 × (700/11) ÷2
= 460 - 2100/11 ÷2
= 5060 - 2100 / 11 ÷2
= 2960/11 ÷2
reciprocal of 2 = 1/2
= 2960 / 11 × 1/2
= 2960/22
x = 1480/ 11
what do u find wrong in this cnt bot 2

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Answer 1

Answer:

equation (2) mai value substitute krne ke baad tumne 2 ka lcm nhi liya aur directly dusre side multiply kr diya

5×(460-3y)/2+4y=800

5×(460-3y)+2*4y=1600

ye mistake h(ʘᴗʘ✿)(◕ᴗ◕✿)(ʘᴗʘ✿)