Math, asked by poonamdhyani1234ksp, 1 month ago

Let coefficient of ratios be X a = 3x b = 4x c = 5x Using Heron's Formula, s = (3+4+5)x/2 = 12x/2 = 6x \begin{gathered} \sqrt{s(s - a)(s - b)(s - c)} \\ \sqrt{6x(6x - 3x)(6x - 4x)(6x - 5x)} \\ \sqrt{6x \times 3x \times 2x \times x} \\ \sqrt{36 {x}^{4} } \\ 6 {x}^{2} \\ area \: given = 150 \: {cm}^{2} \\ so. \\ 6 {x}^{2} = 150 \\ {x}^{2} = \frac{150}{6} \\ {x}^{2} = 25 \\ x = \sqrt{25} = 5 \: cm\end{gathered} s(s−a)(s−b)(s−c) 6x(6x−3x)(6x−4x)(6x−5x) 6x×3x×2x×x 36x 4 6x 2 areagiven=150cm 2 so. 6x 2 =150 x 2 = 6 150 x 2 =25 x= 25 =5cm.

Answers

Answered by nithya12333
1

write the question more clearly dear

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