let cosA = cos54 then a/2
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1
=> cosA = cos54 then A=54
=> A/2 = 54/2 = 27
therefore the answer is 27
I think this is the answer.....I hope this helps u
Answered by
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Here is your answer:-
Let A = 18°
Therefore, 5A = 90°
⇒ 2A + 3A = 90˚
⇒ 2θ = 90˚ - 3A
Taking sine on both sides, we get
sin 2A = sin (90˚ - 3A) = cos 3A
⇒ 2 sin A cos A = 4 cos3
3
A - 3 cos A
⇒ 2 sin A cos A - 4 cos3
3
A + 3 cos A = 0
⇒ cos A (2 sin A - 4 cos2
2
A + 3) = 0
Hope it help you
Plz mark me as Brainlist
Let A = 18°
Therefore, 5A = 90°
⇒ 2A + 3A = 90˚
⇒ 2θ = 90˚ - 3A
Taking sine on both sides, we get
sin 2A = sin (90˚ - 3A) = cos 3A
⇒ 2 sin A cos A = 4 cos3
3
A - 3 cos A
⇒ 2 sin A cos A - 4 cos3
3
A + 3 cos A = 0
⇒ cos A (2 sin A - 4 cos2
2
A + 3) = 0
Hope it help you
Plz mark me as Brainlist
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