Let D(3,-2), E(-3,1) and F(4, -3) be the midpoints of the sides
BC, CA and AB respectively of AABC. Then, find the coordinates of
the vertices A, B and C.
Answers
Given,
D(3,-2), E(-3,1) and F(4, -3) be the midpoints of the sides BC, CA and AB respectively of ΔABC.
To Find,
coordinates of the vertices A, B and C.
Solution,
1.
(x₂ + x₃/2) = 3
==> x₂ + x₃ = 6
2.
y₂ + y₃/2 = -2
==> y₂ + y₃ = -4
3.
(x₃ + x₁)/2 = -3
==> x₃ + x₁ = -6
4.
(y₃ + y₁)/2 = 1
==> y₃ + y₁ = 2
5.
(x₁ + x₂)/2 = 4
==> x₁ + x₂ = 8
6.
(y₁ + y₂)/2 = -3
==> y₁ + y₂ = -6
From (1) and (3).
==> x₂ + x₃ - x₃ - x₁ = 12
==> x₂ - x₁ = 12 ------ (7)
Solve (5) and (7).
2x₂ = 20
==> x₂ = 10
x₁ + x₂ - x₂ + x₁ = 8 - 12
==> 2x₁ = -4
==> x₁ = -2
Place x₁ = -2 in (3).
x₃ + x₁ = -6
==> x₃ - 2 = -6
==> x₃ = -4
Subtract (4) and (2).
y₂ - y₁ = -6 ---- (7)
Solve (7) with (8)
y₂ - y₁ + y₂ + y₁ = -6 - 6
2y₂ = -12
y₂ = -6
Place y₂ in (6).
==> y₁ + y₂ = -6
==> y₁ - 6 = -6
==> y₁ = 0
Place y₁ in (4).
y₃ + 0 = 2
==> y₃ = 2
Result:
Coordinates are A(-2,0), B(10,-6), C(-4,2)