Question

Let "D" be a positive number such that when 109 is divided by "D", the remainder is 4. Compute the sum of all possible two-digit values of "D"

Answer 1

Answer:

71

Step-by-step explanation:

let, Quotient is n

D x n +4= 109

D x n = 105

Now, 105= 1 x 105

               =3 x 35

               =5 x 21

               =7 x 15

two digit values are 35, 15, 21

sum= 35+21+15=71