Math, asked by haiderjaved015, 3 months ago

. Let D be a simple graph on 10 vertices such that there is a vertex of degree 1, a vertex of degree 2, a vertex of degree 3, a vertex of degree 4, a vertex of degree 5, a vertex of degree 6, a vertex of degree 7, a vertex of degree 8 and a vertex of degree 9. What can be the degree of the last vertex?
a) 4
b) 0
c) 2
d) 5​

Answers

Answered by amitnrw
6

Given : D be a simple graph on 10 vertices such that there is

a vertex of degree 1,

a vertex of degree 2,

a vertex of degree 3,

a vertex of degree 4,

a vertex of degree 5,

a vertex of degree 6,

a vertex of degree 7,

a vertex of degree 8 an

d a vertex of degree 9

To Find : What can be the degree of the last vertex

a) 4

b) 0

c) 2

d) 5​

Solution:

a vertex of degree 1

a vertex of degree 2

upto

vertex of degree 9

Total Degrees = ( 1 + 2 + 3 + . + . + . + 9)

= 9(10)/2

= 45

Number of  digress  are twice the number of the edges in the graph.

Hence Number of  digress are always even

degree of the last vertex can be 5   only

as 45 + 5 = 50  is only possible even degree

Rest all other options leads to odd numbers ( 45 + 4 = 49 , 45 + 0 = 45 , 45 + 2 = 47)

degree of the last vertex can be 5

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