Question

Let d be the hcf of 24 and 36. Find the two numbers a and b such that d= 24a +36b

Answer 1

Answer:

24=2×2×2×3

36=2×2×3×3

HCF=2×2×3

=12

D =12

12= 24×2(A) +36×-1(B)

A=2 AND B=-1

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Answer 2

Answer to the question is given below.

Using euclids division lemma find the hcf and the we can find the answ