Let “d”be the HCF of 24 and 36 .Find two numbers a and b such that d=24a+36b
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Step-by-step explanation:
Let us consider the problem:
d=HCF of 24 and 36
To find a and b such that d=24a+36b
Applying Euclid's Division Lemma to 24 and 36, we get
36=24(1)+12−−−−−(1)
24=2(12)+0
Thus,the HCF of 24 and 36 is 12.
From(1), we have
Implies that
12=36−24
Implies that
12=24(−1)+36(1)
Implies that
12=24a+36b
Where a=−1 and b=1
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