Math, asked by InduBhonsle21, 1 month ago

Let “d”be the HCF of 24 and 36 .Find two numbers a and b such that d=24a+36b

Answers

Answered by parveenbegum7729
3

Step-by-step explanation:

Let us consider the problem:

d=HCF of 24 and 36

To find a and b such that d=24a+36b

Applying Euclid's Division Lemma to 24 and 36, we get

36=24(1)+12−−−−−(1)

24=2(12)+0

Thus,the HCF of 24 and 36 is 12.

From(1), we have

Implies that

12=36−24

Implies that

12=24(−1)+36(1)

Implies that

12=24a+36b

Where a=−1 and b=1

◇◇Hope it will help you◇◇

Answered by vaibhav9095
2

Answer:

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