Question

Let d ∈ R, and A = , θ ∈ [0, 2π]. If the minimum value of det(A) is 8, then a value of d is:
(A) –5 (B) –7
(C) 2(√2 + 1) (D) 2(√2 + 2)

Answer 1

Answer:

(A)

Step-by-step explanation:

hence d=-5,1

As per options d= -5