Question

Let data rate of 128 QAM signal be 14 kbps. Find the maximum bandwidth required transmit this signal?

Answer 1

Answer:

The maximum bandwidth will be 4000 kHz.

Explanation:

As per the question

We have given that,

Bit rate = 14 kbps

Number of levels = N = 128 QAM

We have to find

the maximum bandwidth required transmit this signal

As we know the maximum amount of data transmitted over an internet connection in a given amount of time.

The basic equation for this is

Total Bandwidth = Packet Size x Packets Per Second.

In theory, bandwidth is related to data rate by:

1) Nyquist formula:

data rate = 2 * bandwidth * log2 (M)  ;     where M is the modulation level (eg., M=4 for QPSK ).

2) Shannon formula:

data rate = bandwidth * log2(1+SNR) ; where SNR is the signal to niose ratio.

= frac { 2 x 14  }{log _2} 128 } kHz )

= 4000 kHz

So , The maximum bandwidth will be 4000 kHz.

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