Question

Let θ denote the angular displacement of a simple pendulum oscillating in a vertical plane. If the mass of the bob is m, the tension is the string is mg cos θ
(a) always
(b) never
(c) at the extreme positions
(d) at the mean position.

Answer 1

Let θ denote the angular displacement of a simple pendulum oscillating in a vertical plane. If the mass of the bob is m, the tension is the string is mg cos θ  at the extreme positions

Explanation:

If we look into the figure given below, the weight of the Bob at the mean position A will be “mg” where m = mass and g = acceleration due to gravity.

Now, the tension produced in the string would be mg in the opposite direction

On resolving the force (weight), the Tension in the extreme positions C and B will be mgcosθ.

Hence, the correct option is (c) i.e. at the extreme positions.

Answer 2

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Let θ denote the angular displacement of a simple pendulum oscillating in a vertical plane. If the mass of the bob is m, the tension is the string is mg cos θ  at the extreme positions

Let θ denote the angular displacement of a simple pendulum oscillating in a vertical plane. If the mass of the bob is m, the tension is the string is mg cos θ  at the extreme positionsExplanation:

Let θ denote the angular displacement of a simple pendulum oscillating in a vertical plane. If the mass of the bob is m, the tension is the string is mg cos θ  at the extreme positionsExplanation:If we look into the figure given below, the weight of the Bob at the mean position A will be “mg” where m = mass and g = acceleration due to gravity.

Let θ denote the angular displacement of a simple pendulum oscillating in a vertical plane. If the mass of the bob is m, the tension is the string is mg cos θ  at the extreme positionsExplanation:If we look into the figure given below, the weight of the Bob at the mean position A will be “mg” where m = mass and g = acceleration due to gravity.Now, the tension produced in the string would be mg in the opposite direction

Let θ denote the angular displacement of a simple pendulum oscillating in a vertical plane. If the mass of the bob is m, the tension is the string is mg cos θ  at the extreme positionsExplanation:If we look into the figure given below, the weight of the Bob at the mean position A will be “mg” where m = mass and g = acceleration due to gravity.Now, the tension produced in the string would be mg in the opposite directionOn resolving the force (weight), the Tension in the extreme positions C and B will be mgcosθ.

Let θ denote the angular displacement of a simple pendulum oscillating in a vertical plane. If the mass of the bob is m, the tension is the string is mg cos θ  at the extreme positionsExplanation:If we look into the figure given below, the weight of the Bob at the mean position A will be “mg” where m = mass and g = acceleration due to gravity.Now, the tension produced in the string would be mg in the opposite directionOn resolving the force (weight), the Tension in the extreme positions C and B will be mgcosθ.Hence, the correct option is (c) i.e. at the extreme positions.

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