Let E be a subset of metric space X
Such that no limit point of E then,
Select one:
A. E is open
B. E is not open
O C. E is not closed.
O D. E is closed
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D. E is closed
GIVEN: E is a subset of metric space X
TO PROOF: E is closed.
SOLUTION:
According to the question,
Let us assume that E is closed.
Now,
x∈ Ec, then x∉E.
So,
x is not the limit point of E.
Hence,
There is a neighborhood N of x.
Such that,
E∩N is empty, where N⊂Ec.
Thus, x is an interior point of Ec and Ec is open.
Now,
Let us assume Ec is open.
Now, let x be a limit point of E, then for every neighborhood of x that contains a point of E such that x is not an interior point of Ec.
Since Ec is open,
This implies that x∈E,
Therefore E is closed.
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